Media Summary: Okay but what is this integral anyhow this is the Fourier Fourier inverse transform of this F of Omega right so we put a You get an approximate impulse something like this and then the weight of this is equal to delta and the height is Okay and then you put an a over here and put the a over there because you put an a over there you have to put a
Uiuc Ece210 L41 1 - Detailed Analysis & Overview
Okay but what is this integral anyhow this is the Fourier Fourier inverse transform of this F of Omega right so we put a You get an approximate impulse something like this and then the weight of this is equal to delta and the height is Okay and then you put an a over here and put the a over there because you put an a over there you have to put a So it has a f of key and then if you modulate it by this strange function n is = to Part c you're given that f of t is equal to 2 cosine of omega And if you were to ask what the resistance is when they're connected in parallel okay the rp that you see in this node here is
This is well know right and we know FN was So i get two t but this is just uh e to the minus plus tau right this Okay so this will retransform to that and then you're given that the input ft is a sine of 2 psi t and f of omega must be equal to Best theorem it says that the power in the time domain integrated is equal to No so we have i think 60 years and it's not section wise it's not such a nice okay anita is
