Media Summary: So i get two t but this is just uh e to the minus plus tau right this You get an approximate impulse something like this and then the weight of this is equal to delta and the height is Okay but what is this integral anyhow this is the Fourier Fourier inverse transform of this F of Omega right so we put a

Uiuc Ece210 L40 1 - Detailed Analysis & Overview

So i get two t but this is just uh e to the minus plus tau right this You get an approximate impulse something like this and then the weight of this is equal to delta and the height is Okay but what is this integral anyhow this is the Fourier Fourier inverse transform of this F of Omega right so we put a And if you were to ask what the resistance is when they're connected in parallel okay the rp that you see in this node here is So it has a f of key and then if you modulate it by this strange function n is = to Okay so this will retransform to that and then you're given that the input ft is a sine of 2 psi t and f of omega must be equal to

Best theorem it says that the power in the time domain integrated is equal to Example 10.3 let's go through this example so it says that if ht is equal to Part c you're given that f of t is equal to 2 cosine of omega No so we have i think 60 years and it's not section wise it's not such a nice okay anita is And then uh you can renormalize this equation so that it look something like J Omega RC minus Omega squ LC +

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UIUC ECE210 L40-1

UIUC ECE210 L40-1

So i get two t but this is just uh e to the minus plus tau right this

UIUC ECE210 L42-1

UIUC ECE210 L42-1

You get an approximate impulse something like this and then the weight of this is equal to delta and the height is

UIUC ECE210 L40-2

UIUC ECE210 L40-2

Okay if you click this

UIUC ECE210 L41-1

UIUC ECE210 L41-1

Okay but what is this integral anyhow this is the Fourier Fourier inverse transform of this F of Omega right so we put a

UIUC ECE 210 4-1

UIUC ECE 210 4-1

And if you were to ask what the resistance is when they're connected in parallel okay the rp that you see in this node here is

UIUC ECE210 L37-1

UIUC ECE210 L37-1

So it has a f of key and then if you modulate it by this strange function n is = to

UIUC ECE 210 L49-1

UIUC ECE 210 L49-1

Minus

UIUC ECE 210 L47-1

UIUC ECE 210 L47-1

Okay so this will retransform to that and then you're given that the input ft is a sine of 2 psi t and f of omega must be equal to

UIUC ECE 210 L44-1

UIUC ECE 210 L44-1

Best theorem it says that the power in the time domain integrated is equal to

UIUC ECE 210 L45-1

UIUC ECE 210 L45-1

Example 10.3 let's go through this example so it says that if ht is equal to

UIUC ECE210 L34-1

UIUC ECE210 L34-1

Part c you're given that f of t is equal to 2 cosine of omega

UIUC ECE 210 1-1

UIUC ECE 210 1-1

No so we have i think 60 years and it's not section wise it's not such a nice okay anita is

UIUC ECE 210 L26-1

UIUC ECE 210 L26-1

And then uh you can renormalize this equation so that it look something like J Omega RC minus Omega squ LC +