Media Summary: Um so they've given us uh Vector a which is Okay question 10 part one um is given us the position vectors of two uh points P which is 5 2 - 9 and Q which is Which is just the magnitude of this Vector here um the vector a to0 which is just the negative of this a to O is going to be minus

Core 4 Ocr Jan 2007 - Detailed Analysis & Overview

Um so they've given us uh Vector a which is Okay question 10 part one um is given us the position vectors of two uh points P which is 5 2 - 9 and Q which is Which is just the magnitude of this Vector here um the vector a to0 which is just the negative of this a to O is going to be minus ... cos we get S so that's going to be sin 4X but we're also going to need to divide by the coefficient of x there which is

Photo Gallery

Core 4 OCR Jan 2007 Q9 - Differential equations (1)
OCR Core 4 Jan 2007 q3i
Core 4 OCR Jan 2007 Q10 - Vector Questions(2)
OCR Core 4 Jan 2007 q10iii
OCR Core 4 Jan 2007 q10i
OCR Core 4 Jan 2007 q3ii
Core 4 OCR Jan 2007 Q3 - Vectors Questions(1)
OCR Core 4 Jan 2007 q10ii
OCR Core 4 Jan 2007 q10iv
Core 4 OCR June 2007 Q6 - Implicit Differentiation (1)
OCR Core 4 Jan 2007 q8iv - A2 Maths - Parametric Equations
OCR Core 4 Jan 2007 q4 - A2 - Maths - Integration by Substitution
View Detailed Profile
Core 4 OCR Jan 2007 Q9 - Differential equations (1)

Core 4 OCR Jan 2007 Q9 - Differential equations (1)

Powered by https://www.numerise.com/

OCR Core 4 Jan 2007 q3i

OCR Core 4 Jan 2007 q3i

Um so they've given us uh Vector a which is

Core 4 OCR Jan 2007 Q10 - Vector Questions(2)

Core 4 OCR Jan 2007 Q10 - Vector Questions(2)

Powered by https://www.numerise.com/

OCR Core 4 Jan 2007 q10iii

OCR Core 4 Jan 2007 q10iii

Okay

OCR Core 4 Jan 2007 q10i

OCR Core 4 Jan 2007 q10i

Okay question 10 part one um is given us the position vectors of two uh points P which is 5 2 - 9 and Q which is

OCR Core 4 Jan 2007 q3ii

OCR Core 4 Jan 2007 q3ii

Which is just the magnitude of this Vector here um the vector a to0 which is just the negative of this a to O is going to be minus

Core 4 OCR Jan 2007 Q3 - Vectors Questions(1)

Core 4 OCR Jan 2007 Q3 - Vectors Questions(1)

Powered by https://www.numerise.com/

OCR Core 4 Jan 2007 q10ii

OCR Core 4 Jan 2007 q10ii

Okay so

OCR Core 4 Jan 2007 q10iv

OCR Core 4 Jan 2007 q10iv

Okay so finally part

Core 4 OCR June 2007 Q6 - Implicit Differentiation (1)

Core 4 OCR June 2007 Q6 - Implicit Differentiation (1)

Powered by https://www.numerise.com/

OCR Core 4 Jan 2007 q8iv - A2 Maths - Parametric Equations

OCR Core 4 Jan 2007 q8iv - A2 Maths - Parametric Equations

Ok question 8 part

OCR Core 4 Jan 2007 q4 - A2 - Maths - Integration by Substitution

OCR Core 4 Jan 2007 q4 - A2 - Maths - Integration by Substitution

Okay question

A Pure Maths - Differential Equations OCR Core 4 Jan 2007 q9i

A Pure Maths - Differential Equations OCR Core 4 Jan 2007 q9i

... cos we get S so that's going to be sin 4X but we're also going to need to divide by the coefficient of x there which is