Media Summary: Um so they've given us uh Vector a which is ... cos we get S so that's going to be sin 4X but we're also going to need to divide by the coefficient of x there which is Which is just the magnitude of this Vector here um the vector a to0 which is just the negative of this a to O is going to be minus

Ocr Core 4 Jan 2007 - Detailed Analysis & Overview

Um so they've given us uh Vector a which is ... cos we get S so that's going to be sin 4X but we're also going to need to divide by the coefficient of x there which is Which is just the magnitude of this Vector here um the vector a to0 which is just the negative of this a to O is going to be minus ... products and see what happens we've got -1 * 1 which is -1 2 * 2 which is ... to need to be point two two sets of brackets and probably with the next take OCR Core 4 Jan 2007 q5ii - A2 Maths - Binomial Expansion

Okay five part one and wants us to expand this up to X cubed so we need Our limits are two and one so when we put two in we're going to get

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OCR Core 4 Jan 2007 q3i
A Pure Maths - Differential Equations OCR Core 4 Jan 2007 q9i
OCR Core 4 Jan 2007 q3ii
OCR Core 4 Jan 2007 q10iii
OCR Core 4 Jan 2007 q10ii
OCR Core 4 Jan 2007 q10iv
OCR Core 4 Jan 2007 q1 - Rational Functions/Algebraic Fractions
OCR Core 4 Jan 2007 q4 - A2 - Maths - Integration by Substitution
A Level Pure Maths - Partial Fractions OCR Core 4 Jan 2007 q6i
OCR Core 4 Jan 2007 q5ii - A2 Maths - Binomial Expansion
OCR Core 4 Jan 2007 q5i - A2 Maths - Binomial Expansion
A Level Pure Maths - Partial Fractions OCR Core 4 Jan 2007 q6ii
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OCR Core 4 Jan 2007 q3i

OCR Core 4 Jan 2007 q3i

Um so they've given us uh Vector a which is

A Pure Maths - Differential Equations OCR Core 4 Jan 2007 q9i

A Pure Maths - Differential Equations OCR Core 4 Jan 2007 q9i

... cos we get S so that's going to be sin 4X but we're also going to need to divide by the coefficient of x there which is

OCR Core 4 Jan 2007 q3ii

OCR Core 4 Jan 2007 q3ii

Which is just the magnitude of this Vector here um the vector a to0 which is just the negative of this a to O is going to be minus

OCR Core 4 Jan 2007 q10iii

OCR Core 4 Jan 2007 q10iii

Zero so that tells me that 2T is

OCR Core 4 Jan 2007 q10ii

OCR Core 4 Jan 2007 q10ii

... products and see what happens we've got -1 * 1 which is -1 2 * 2 which is

OCR Core 4 Jan 2007 q10iv

OCR Core 4 Jan 2007 q10iv

Okay so finally part

OCR Core 4 Jan 2007 q1 - Rational Functions/Algebraic Fractions

OCR Core 4 Jan 2007 q1 - Rational Functions/Algebraic Fractions

... to need to be point two two sets of brackets and probably with the next take

OCR Core 4 Jan 2007 q4 - A2 - Maths - Integration by Substitution

OCR Core 4 Jan 2007 q4 - A2 - Maths - Integration by Substitution

Okay question

A Level Pure Maths - Partial Fractions OCR Core 4 Jan 2007 q6i

A Level Pure Maths - Partial Fractions OCR Core 4 Jan 2007 q6i

... one I'm going to choose an X to be

OCR Core 4 Jan 2007 q5ii - A2 Maths - Binomial Expansion

OCR Core 4 Jan 2007 q5ii - A2 Maths - Binomial Expansion

OCR Core 4 Jan 2007 q5ii - A2 Maths - Binomial Expansion

OCR Core 4 Jan 2007 q5i - A2 Maths - Binomial Expansion

OCR Core 4 Jan 2007 q5i - A2 Maths - Binomial Expansion

Okay five part one and wants us to expand this up to X cubed so we need

A Level Pure Maths - Partial Fractions OCR Core 4 Jan 2007 q6ii

A Level Pure Maths - Partial Fractions OCR Core 4 Jan 2007 q6ii

When

OCR Core 4 Jan 2007 q2 - A2 - Maths - Integration by Parts

OCR Core 4 Jan 2007 q2 - A2 - Maths - Integration by Parts

Our limits are two and one so when we put two in we're going to get