Media Summary: That's why we got one in here but any other places that we have pi or Omega right we know this so now as we we know this Omega 0 is ... minus c conjugation okay if i subtract these

Uiuc Ece210 L31 2 - Detailed Analysis & Overview

That's why we got one in here but any other places that we have pi or Omega right we know this so now as we we know this Omega 0 is ... minus c conjugation okay if i subtract these Minus 1 to t minus 1 to t which is this integration over here and then Okay where's the first zero Crossing of this function what Omega have to be or what Omega Tau over Part c you're given that f of t is equal to

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UIUC ECE210 L31-2
UIUC ECE210 L31-1
UIUC ECE210 L32-2
UIUC ECE 210 4-2
UIUC ECE 210 3-2
UIUC ECE 210 L29-2
UIUC ECE210 L30-2
UIUC ECE210 L30-1
UIUC ECE 210 L49-1
UIUC ECE210 L35-1
UIUC ECE 210 24-2
UIUC ECE210 L34-1
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UIUC ECE210 L31-2

UIUC ECE210 L31-2

That's why we got one in here but any other places that we have pi or

UIUC ECE210 L31-1

UIUC ECE210 L31-1

Omega right we know this so now as we we know this Omega 0 is

UIUC ECE210 L32-2

UIUC ECE210 L32-2

Drops and

UIUC ECE 210 4-2

UIUC ECE 210 4-2

V2

UIUC ECE 210 3-2

UIUC ECE 210 3-2

... minus c conjugation okay if i subtract these

UIUC ECE 210 L29-2

UIUC ECE 210 L29-2

1 over minus j n

UIUC ECE210 L30-2

UIUC ECE210 L30-2

Guy and 8 over piun

UIUC ECE210 L30-1

UIUC ECE210 L30-1

Plus 8 over 3 pi cosine of pi over

UIUC ECE 210 L49-1

UIUC ECE 210 L49-1

Minus 1 to t minus 1 to t which is this integration over here and then

UIUC ECE210 L35-1

UIUC ECE210 L35-1

Okay where's the first zero Crossing of this function what Omega have to be or what Omega Tau over

UIUC ECE 210 24-2

UIUC ECE 210 24-2

Minus

UIUC ECE210 L34-1

UIUC ECE210 L34-1

Part c you're given that f of t is equal to

UIUC ECE 210 2-2

UIUC ECE 210 2-2

No okay you solve these