Media Summary: Okay example uh 11 section 11.2.3 these are quite interesting examples h head of s is equal to s over s plus Example 10.3 let's go through this example so it says that if ht is equal to What a paul is okay a pole is a point where the function like the laplace transform goes infinity so s equals to

Uiuc Ece 210 L50 1 - Detailed Analysis & Overview

Okay example uh 11 section 11.2.3 these are quite interesting examples h head of s is equal to s over s plus Example 10.3 let's go through this example so it says that if ht is equal to What a paul is okay a pole is a point where the function like the laplace transform goes infinity so s equals to No so we have i think 60 years and it's not section wise it's not such a nice okay anita is Okay no question Then um let's figure out how we can get a formula such as this Best theorem it says that the power in the time domain integrated is equal to

So summing that gives me b minus so i have v minus being equal to v 0 The other equation that you should have is that v1 divided by And then the numerator and the denominator can also be written as a polynomial it can be written as n plus a

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UIUC ECE 210 L50-1

UIUC ECE 210 L50-1

Function you have r of s is equal to say

UIUC ECE 210 L51-1

UIUC ECE 210 L51-1

Okay and in this example everything is

UIUC ECE 210 L50-2

UIUC ECE 210 L50-2

Okay example uh 11 section 11.2.3 these are quite interesting examples h head of s is equal to s over s plus

UIUC ECE 210 L49-1

UIUC ECE 210 L49-1

Minus

UIUC ECE 210 L45-1

UIUC ECE 210 L45-1

Example 10.3 let's go through this example so it says that if ht is equal to

UIUC ECE 210 L48-1

UIUC ECE 210 L48-1

What a paul is okay a pole is a point where the function like the laplace transform goes infinity so s equals to

UIUC ECE 210 1-1

UIUC ECE 210 1-1

No so we have i think 60 years and it's not section wise it's not such a nice okay anita is

UIUC ECE 210 L27-1

UIUC ECE 210 L27-1

Okay no question Then um let's figure out how we can get a formula such as this

UIUC ECE 210 1-2

UIUC ECE 210 1-2

Charge 10 to the minus 90. so

UIUC ECE 210 L44-1

UIUC ECE 210 L44-1

Best theorem it says that the power in the time domain integrated is equal to

UIUC ECE 210 11-1

UIUC ECE 210 11-1

So summing that gives me b minus so i have v minus being equal to v 0

UIUC ECE 210 5-1

UIUC ECE 210 5-1

The other equation that you should have is that v1 divided by

UIUC ECE 210 L51-2

UIUC ECE 210 L51-2

And then the numerator and the denominator can also be written as a polynomial it can be written as n plus a