Media Summary: Solving an unusual functional equation from Solving a trigonometric equation. We consider three cases separately, making various estimations along the way to deduce theĀ ... Proving an inequality with cosines. This problem is rather easy if you know the formula for cos(x – y). This problem was takenĀ ...

Romanian Imo Team Selection Test - Detailed Analysis & Overview

Solving an unusual functional equation from Solving a trigonometric equation. We consider three cases separately, making various estimations along the way to deduce theĀ ... Proving an inequality with cosines. This problem is rather easy if you know the formula for cos(x – y). This problem was takenĀ ... A beautiful number-theoretic problem from Solving a functional inequality. We make use of a symmetry we notice, and then we show that our function must be constant on theĀ ... Instructor: Jasiah Azmain Facebook Id Link: Website Link: Ā ...

Finding all pairs of functions satisfying given functional equation, given additionally that one of them should be strictly monotonic. Showing a crazy-looking divisibility from the Showing that 3ⁿ – 2ⁿ is almost never divisible by n. We use Fermat's little theorem as well as well-known fact about the greatestĀ ... This is a difficult problem from the 2012 Hello everyone so this is the hong kong tst 1994 the This problem could easily be solved by approximating each radical but approximation was the only thing you were not allowed toĀ ...

Photo Gallery

Romanian IMO Team Selection Test, 1996, problem 1
Romanian IMO Team Selection Test, 1978, problem 17
Romanian IMO Team Selection Test, 1987, problem 9
Romanian IMO Team Selection Test, 1996, problem 11
Estonian IMO Team Selection Test, 2022, problem 1
šŸ›‘803. 2002 Romanian Team Selection Test || Junior Balkan Mathematical Olympiad || BDMO
Romanian IMO Team Selection Test, 1998, problem 14
Romanian IMO Team Selection Test, 1994, problem 2
Romanian IMO Team Selection Test, 1987, problem 7
Some Junior Math Competitions Problems are as hard as the IMO - Romania JBMO TST 2012 Day 3 - P4
Hong Kong TST 1994 (Team Selection Test for International Mathematical Olympiad (IMO)) Problem 1
IMSC 2025: IMO Showcase Lecture - Dinu Serbanescu (Bucharest)
View Detailed Profile
Romanian IMO Team Selection Test, 1996, problem 1

Romanian IMO Team Selection Test, 1996, problem 1

Solving an unusual functional equation from

Romanian IMO Team Selection Test, 1978, problem 17

Romanian IMO Team Selection Test, 1978, problem 17

Solving a trigonometric equation. We consider three cases separately, making various estimations along the way to deduce theĀ ...

Romanian IMO Team Selection Test, 1987, problem 9

Romanian IMO Team Selection Test, 1987, problem 9

Proving an inequality with cosines. This problem is rather easy if you know the formula for cos(x – y). This problem was takenĀ ...

Romanian IMO Team Selection Test, 1996, problem 11

Romanian IMO Team Selection Test, 1996, problem 11

A beautiful number-theoretic problem from

Estonian IMO Team Selection Test, 2022, problem 1

Estonian IMO Team Selection Test, 2022, problem 1

Solving a functional inequality. We make use of a symmetry we notice, and then we show that our function must be constant on theĀ ...

šŸ›‘803. 2002 Romanian Team Selection Test || Junior Balkan Mathematical Olympiad || BDMO

šŸ›‘803. 2002 Romanian Team Selection Test || Junior Balkan Mathematical Olympiad || BDMO

Instructor: Jasiah Azmain Facebook Id Link: https://www.facebook.com/profile.php?id=100077902145986 Website Link: Ā ...

Romanian IMO Team Selection Test, 1998, problem 14

Romanian IMO Team Selection Test, 1998, problem 14

Finding all pairs of functions satisfying given functional equation, given additionally that one of them should be strictly monotonic.

Romanian IMO Team Selection Test, 1994, problem 2

Romanian IMO Team Selection Test, 1994, problem 2

Showing a crazy-looking divisibility from the

Romanian IMO Team Selection Test, 1987, problem 7

Romanian IMO Team Selection Test, 1987, problem 7

Showing that 3ⁿ – 2ⁿ is almost never divisible by n. We use Fermat's little theorem as well as well-known fact about the greatestĀ ...

Some Junior Math Competitions Problems are as hard as the IMO - Romania JBMO TST 2012 Day 3 - P4

Some Junior Math Competitions Problems are as hard as the IMO - Romania JBMO TST 2012 Day 3 - P4

This is a difficult problem from the 2012

Hong Kong TST 1994 (Team Selection Test for International Mathematical Olympiad (IMO)) Problem 1

Hong Kong TST 1994 (Team Selection Test for International Mathematical Olympiad (IMO)) Problem 1

Hello everyone so this is the hong kong tst 1994 the

IMSC 2025: IMO Showcase Lecture - Dinu Serbanescu (Bucharest)

IMSC 2025: IMO Showcase Lecture - Dinu Serbanescu (Bucharest)

Title:

Romanian Mathematics Olympiad

Romanian Mathematics Olympiad

This problem could easily be solved by approximating each radical but approximation was the only thing you were not allowed toĀ ...