Media Summary: MAC 1114/1140/1147 Chapter 2 Section 2 Part 1 ... into our original function wherever there's an x so in our original function we have a Well we'd start with our f and then we see another set of parentheses after that which is another of and then we see our last

Mac 1114 Chapter 2 Section - Detailed Analysis & Overview

MAC 1114/1140/1147 Chapter 2 Section 2 Part 1 ... into our original function wherever there's an x so in our original function we have a Well we'd start with our f and then we see another set of parentheses after that which is another of and then we see our last Well no what we're gonna do is shift everything to the right Let's try one last one like this looking at this next one we're going to start with let's see f of f of negative 1 and again we' ... both sides which gives me that y equals well I'm dividing everything through by negative 1 so that'

Let's take a look at graphene some functions the first thing that we'

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MAC 1114/1140/1147 Chapter 2 Section 8 Part 1
MAC 1114/1140/1147 Chapter 2 Section 2 Part 1
MAC 1114/1140/1147 Chapter 2 Section 3 Part 1
MAC 1114/1140/1147 Chapter 2 Section 8 Part 2
MAC 1114/1140/1147 Chapter 2 Section 7 Part 1
MAC 1114/1140/1147 Chapter 2 Section 8 Part 5
MAC 1114 Chapter 2 Section 7 Part 7
MAC 1114/1140/1147 Chapter 2 Section 7 Part 5
MAC 1114/1140/1147 Chapter 2 Section 8 Part 6
MAC 1114/1140/1147 Chapter 2 Section 8 Part 10
MAC 1114/1140/1147 Chapter 2 Section 7 Part 9
MAC 1114/1140/1147 Chapter 2 Section 7 Part 2
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MAC 1114/1140/1147 Chapter 2 Section 8 Part 1

MAC 1114/1140/1147 Chapter 2 Section 8 Part 1

Now let's take a look at

MAC 1114/1140/1147 Chapter 2 Section 2 Part 1

MAC 1114/1140/1147 Chapter 2 Section 2 Part 1

MAC 1114/1140/1147 Chapter 2 Section 2 Part 1

MAC 1114/1140/1147 Chapter 2 Section 3 Part 1

MAC 1114/1140/1147 Chapter 2 Section 3 Part 1

In

MAC 1114/1140/1147 Chapter 2 Section 8 Part 2

MAC 1114/1140/1147 Chapter 2 Section 8 Part 2

... into our original function wherever there's an x so in our original function we have a

MAC 1114/1140/1147 Chapter 2 Section 7 Part 1

MAC 1114/1140/1147 Chapter 2 Section 7 Part 1

In

MAC 1114/1140/1147 Chapter 2 Section 8 Part 5

MAC 1114/1140/1147 Chapter 2 Section 8 Part 5

Well we'd start with our f and then we see another set of parentheses after that which is another of and then we see our last

MAC 1114 Chapter 2 Section 7 Part 7

MAC 1114 Chapter 2 Section 7 Part 7

Well no what we're gonna do is shift everything to the right

MAC 1114/1140/1147 Chapter 2 Section 7 Part 5

MAC 1114/1140/1147 Chapter 2 Section 7 Part 5

Not quite 1/

MAC 1114/1140/1147 Chapter 2 Section 8 Part 6

MAC 1114/1140/1147 Chapter 2 Section 8 Part 6

Those two are opposite so they'

MAC 1114/1140/1147 Chapter 2 Section 8 Part 10

MAC 1114/1140/1147 Chapter 2 Section 8 Part 10

Let's try one last one like this looking at this next one we're going to start with let's see f of f of negative 1 and again we'

MAC 1114/1140/1147 Chapter 2 Section 7 Part 9

MAC 1114/1140/1147 Chapter 2 Section 7 Part 9

... both sides which gives me that y equals well I'm dividing everything through by negative 1 so that'

MAC 1114/1140/1147 Chapter 2 Section 7 Part 2

MAC 1114/1140/1147 Chapter 2 Section 7 Part 2

Let's take a look at graphene some functions the first thing that we'

MAC 1114/1140/1147 Chapter 2 Section 8 Part 7

MAC 1114/1140/1147 Chapter 2 Section 8 Part 7

Now let's try