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In the fig angle BED= angle BDE and E divides BC in the ratio 2:1. Prove that AF×BE = 2AD×CF

In the fig angle BED= angle BDE and E divides BC in the ratio 2:1. Prove that AF×BE = 2AD×CF

Class-10 Maths Chapter-6, Triangles

In the figure, angle BED = angle BDE and E is the mid point of BC. Prove that AF/CF = AD/BE.

In the figure, angle BED = angle BDE and E is the mid point of BC. Prove that AF/CF = AD/BE.

#2_pi_classes #class10maths #InthefigureangleBEDisequaltoangleBDEandEisthemidpointofBC ...

In the adjoining figure, AD/BD = AE/EC and angle BDE = angle CED, prove that triangle ABC is an isos

In the adjoining figure, AD/BD = AE/EC and angle BDE = angle CED, prove that triangle ABC is an isos

In the adjoining figure, AD/BD = AE/EC and angle BDE = angle CED, prove that triangle ABC is an isosceles triangle. Class 10th ...