Media Summary: Support Me On Patreon: if you enjoyed this video, feel free to hit the ... In Prob. 2.25, you found the potential on the axis of a uniformly charged disk: V(r, 0) = σ/2ε0 (√r2+R2-r) . (a) Use this, together with ... All you have to do is match the coefficient of the terms with the same power.
Griffiths Problem 3 22 Solution - Detailed Analysis & Overview
Support Me On Patreon: if you enjoyed this video, feel free to hit the ... In Prob. 2.25, you found the potential on the axis of a uniformly charged disk: V(r, 0) = σ/2ε0 (√r2+R2-r) . (a) Use this, together with ... All you have to do is match the coefficient of the terms with the same power. A subtle point requires us to tweak our constants a bit for the 'southern hemisphere' in order to get our boundary conditions to ... electric potential a distance S from an infinitely long straight wire carrying uniform charge density Lambda.
