Media Summary: Again just making a note of this this is all of our answers between 0 & When is sine equal to 1 and 90 degrees at PI over But that's only once around the circle and if X is from 0 to
40sp2 7 2 Example 2 - Detailed Analysis & Overview
Again just making a note of this this is all of our answers between 0 & When is sine equal to 1 and 90 degrees at PI over But that's only once around the circle and if X is from 0 to There's no X in there so it'd just be 10 of PI over 4 so this is simplifying that one now for this Now the problem at this point is that we have the square root of one half and we don't have that on our unit circle ok we have 1/ Is between quadrants I sorry is between 0 and PI over
Like a general solution I like to first solve between 0 & Yeah so for a we've got co^ squ pi over 4 minus sin^
