Media Summary: Actually, k=2, 11, 22 is the full set of possible k values. I skipped over k=2 when I first did this A good example of using the generator functions for reduced Pythagorean triples: For every pair of positive integers (t, s) that are ... QUESTION from Long Le: Why can we equate the fractional part of the numbers? I mean, couldn't you just add the integral to ...

2016 Aime Prob 5 - Detailed Analysis & Overview

Actually, k=2, 11, 22 is the full set of possible k values. I skipped over k=2 when I first did this A good example of using the generator functions for reduced Pythagorean triples: For every pair of positive integers (t, s) that are ... QUESTION from Long Le: Why can we equate the fractional part of the numbers? I mean, couldn't you just add the integral to ... To tidy up this last detail, we need to show that the solutions we find after stripping away the logs do not force any of the log( ) ... STEMerch : SUb to Competitive Playlist: ... Note that we apply the negative sign to the smaller-magnitude number in the factor pair to satisfy the condition that (a+b) is ...

We creatively combine the two expressions to find the value of the desired expression. Your support is truly a huge ...

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2016 AIME Prob 5
2016 AIME II Prob 5
2016 AIME 2 Question 5
2016 AIME 1 Question 5
2016 AIME Prob 6
an interesting geometry problem (2016 AIME II #5)
2017 AIME Prob 5
2018 AIME Prob 5
AIME 1986 Problem 5
2016 AIME Prob 4
2016 AIME Prob 7
2016 AIME Prob 8
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2016 AIME Prob 5

2016 AIME Prob 5

Actually, k=2, 11, 22 is the full set of possible k values. I skipped over k=2 when I first did this

2016 AIME II Prob 5

2016 AIME II Prob 5

A good example of using the generator functions for reduced Pythagorean triples: For every pair of positive integers (t, s) that are ...

2016 AIME 2 Question 5

2016 AIME 2 Question 5

2016 AIME

2016 AIME 1 Question 5

2016 AIME 1 Question 5

2016 AIME

2016 AIME Prob 6

2016 AIME Prob 6

Incenter/Excenter leads quickly to AD=

an interesting geometry problem (2016 AIME II #5)

an interesting geometry problem (2016 AIME II #5)

This

2017 AIME Prob 5

2017 AIME Prob 5

QUESTION from Long Le: Why can we equate the fractional part of the numbers? I mean, couldn't you just add the integral to ...

2018 AIME Prob 5

2018 AIME Prob 5

To tidy up this last detail, we need to show that the solutions we find after stripping away the logs do not force any of the log( ) ...

AIME 1986 Problem 5

AIME 1986 Problem 5

STEMerch @Twitter: https://twitter.com/merch_ste SUb to @NPCooking69 Competitive Playlist: ...

2016 AIME Prob 4

2016 AIME Prob 4

AIME problem

2016 AIME Prob 7

2016 AIME Prob 7

Note that we apply the negative sign to the smaller-magnitude number in the factor pair to satisfy the condition that (a+b) is ...

2016 AIME Prob 8

2016 AIME Prob 8

AIME problem

2010 AIME II Problem 5 (Logarithm, Expressions)

2010 AIME II Problem 5 (Logarithm, Expressions)

We creatively combine the two expressions to find the value of the desired expression. Your support is truly a huge ...